"As reported in the New York Times, the code pertains to an as-yet-undecrypted final part of Sanborn's Kryptos, which was dedicated by the CIA in 1990. The sculpture features four passages of seemingly jumbled text, three of which have been decoded by amateur and professional cryptologists. "But the fourth passage, which is 97 characters long, has resisted the best efforts of brain and silicon," as described by John Schwartz, a retired Times writer who has been reporting on the quest to solve the Kryptos code."
""Mr. Sanborn, who recently turned 80, decided to sell the final passage, known as K4, earlier this year," Schwartz writes. "He had wearied of dealing for decades with fans who wanted to know whether they had solved the puzzle. He hoped to pass on to others the tasks of keeping the secret and responding to queries." It turned out that, earlier this year, a writer found material containing the solution to the mystery"
An anonymous buyer purchased the final passage of Jim Sanborn's Kryptos sculpture at an RR Auction sale for a total of $962,500. Kryptos, dedicated at the CIA headquarters in Langley in 1990, contains four passages of encoded text; three have been decoded while the fourth, K4, is a 97-character sequence that remains unsolved. Sanborn sold K4 after growing weary of decades of inquiries from fans and hoped to pass responsibility for the secret to others. Earlier a writer found material in the Smithsonian's Archives of American Art that appeared to contain the solution, casting the auction into question, but the sale proceeded with a $770,000 final bid plus fees.
Read at ARTnews.com
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